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A 3.20kg fish is attached to the lower end of a vertical spring
A 3.20kg fish is attached to the lower end of a vertical spring that has negligible mass and force constant 905N/m . The spring initially is neither stretched nor compressed. The fish is released from rest.
1- What is its speed after it has descended 0.0460m from its initial position? Express your answer with the appropriate units.
2- What is the maximum speed of the fish as it descends? Express your answer with the appropriate units.
Hint
Management"1) Let the velocity be v after it descends by .046 mNow, the loss of PE is equal to the gain of spring energy + 1/2 mv²Therefore, 3.2 x 9.8 x .046 would be qual to 1/2 x 905 x .046² + 1/2 x 3.2 x v²which would be equal to = 1.4425 = .9575 + 1.6 v²Therefore, ...
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